16x^2+16x=12

Solution for 16x^2+16x=12 equation:

16x^2+16x=12

We move all terms to the left:

16x^2+16x-(12)=0

a = 16; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·16·(-12)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-32}{2*16}=\frac{-48}{32}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+32}{2*16}=\frac{16}{32}
=1/2
$